Wed, 31 Dec 2014 06:09:35 +0100
Cloned upstream origin tor-browser at tor-browser-31.3.0esr-4.5-1-build1
revision ID fc1c9ff7c1b2defdbc039f12214767608f46423f for hacking purpose.
michael@0 | 1 | /* -*- Mode: C++; tab-width: 2; indent-tabs-mode: nil; c-basic-offset: 2 -*- */ |
michael@0 | 2 | /* This Source Code Form is subject to the terms of the Mozilla Public |
michael@0 | 3 | * License, v. 2.0. If a copy of the MPL was not distributed with this |
michael@0 | 4 | * file, You can obtain one at http://mozilla.org/MPL/2.0/. */ |
michael@0 | 5 | |
michael@0 | 6 | |
michael@0 | 7 | /** |
michael@0 | 8 | File Name: 15.8.2.18.js |
michael@0 | 9 | ECMA Section: 15.8.2.18 tan( x ) |
michael@0 | 10 | Description: return an approximation to the tan of the |
michael@0 | 11 | argument. argument is expressed in radians |
michael@0 | 12 | special cases: |
michael@0 | 13 | - if x is NaN result is NaN |
michael@0 | 14 | - if x is 0 result is 0 |
michael@0 | 15 | - if x is -0 result is -0 |
michael@0 | 16 | - if x is Infinity or -Infinity result is NaN |
michael@0 | 17 | Author: christine@netscape.com |
michael@0 | 18 | Date: 7 july 1997 |
michael@0 | 19 | */ |
michael@0 | 20 | |
michael@0 | 21 | var SECTION = "15.8.2.18"; |
michael@0 | 22 | var VERSION = "ECMA_1"; |
michael@0 | 23 | startTest(); |
michael@0 | 24 | var TITLE = "Math.tan(x)"; |
michael@0 | 25 | var EXCLUDE = "true"; |
michael@0 | 26 | |
michael@0 | 27 | writeHeaderToLog( SECTION + " "+ TITLE); |
michael@0 | 28 | |
michael@0 | 29 | new TestCase( SECTION, |
michael@0 | 30 | "Math.tan.length", |
michael@0 | 31 | 1, |
michael@0 | 32 | Math.tan.length ); |
michael@0 | 33 | |
michael@0 | 34 | new TestCase( SECTION, |
michael@0 | 35 | "Math.tan()", |
michael@0 | 36 | Number.NaN, |
michael@0 | 37 | Math.tan() ); |
michael@0 | 38 | |
michael@0 | 39 | new TestCase( SECTION, |
michael@0 | 40 | "Math.tan(void 0)", |
michael@0 | 41 | Number.NaN, |
michael@0 | 42 | Math.tan(void 0)); |
michael@0 | 43 | |
michael@0 | 44 | new TestCase( SECTION, |
michael@0 | 45 | "Math.tan(null)", |
michael@0 | 46 | 0, |
michael@0 | 47 | Math.tan(null) ); |
michael@0 | 48 | |
michael@0 | 49 | new TestCase( SECTION, |
michael@0 | 50 | "Math.tan(false)", |
michael@0 | 51 | 0, |
michael@0 | 52 | Math.tan(false) ); |
michael@0 | 53 | |
michael@0 | 54 | new TestCase( SECTION, |
michael@0 | 55 | "Math.tan(NaN)", |
michael@0 | 56 | Number.NaN, |
michael@0 | 57 | Math.tan(Number.NaN) ); |
michael@0 | 58 | |
michael@0 | 59 | new TestCase( SECTION, |
michael@0 | 60 | "Math.tan(0)", |
michael@0 | 61 | 0, |
michael@0 | 62 | Math.tan(0)); |
michael@0 | 63 | |
michael@0 | 64 | new TestCase( SECTION, |
michael@0 | 65 | "Math.tan(-0)", |
michael@0 | 66 | -0, |
michael@0 | 67 | Math.tan(-0)); |
michael@0 | 68 | |
michael@0 | 69 | new TestCase( SECTION, |
michael@0 | 70 | "Math.tan(Infinity)", |
michael@0 | 71 | Number.NaN, |
michael@0 | 72 | Math.tan(Number.POSITIVE_INFINITY)); |
michael@0 | 73 | |
michael@0 | 74 | new TestCase( SECTION, |
michael@0 | 75 | "Math.tan(-Infinity)", |
michael@0 | 76 | Number.NaN, |
michael@0 | 77 | Math.tan(Number.NEGATIVE_INFINITY)); |
michael@0 | 78 | |
michael@0 | 79 | new TestCase( SECTION, |
michael@0 | 80 | "Math.tan(Math.PI/4)", |
michael@0 | 81 | 1, |
michael@0 | 82 | Math.tan(Math.PI/4)); |
michael@0 | 83 | |
michael@0 | 84 | new TestCase( SECTION, |
michael@0 | 85 | "Math.tan(3*Math.PI/4)", |
michael@0 | 86 | -1, |
michael@0 | 87 | Math.tan(3*Math.PI/4)); |
michael@0 | 88 | |
michael@0 | 89 | new TestCase( SECTION, |
michael@0 | 90 | "Math.tan(Math.PI)", |
michael@0 | 91 | -0, |
michael@0 | 92 | Math.tan(Math.PI)); |
michael@0 | 93 | |
michael@0 | 94 | new TestCase( SECTION, |
michael@0 | 95 | "Math.tan(5*Math.PI/4)", |
michael@0 | 96 | 1, |
michael@0 | 97 | Math.tan(5*Math.PI/4)); |
michael@0 | 98 | |
michael@0 | 99 | new TestCase( SECTION, |
michael@0 | 100 | "Math.tan(7*Math.PI/4)", |
michael@0 | 101 | -1, |
michael@0 | 102 | Math.tan(7*Math.PI/4)); |
michael@0 | 103 | |
michael@0 | 104 | new TestCase( SECTION, |
michael@0 | 105 | "Infinity/Math.tan(-0)", |
michael@0 | 106 | -Infinity, |
michael@0 | 107 | Infinity/Math.tan(-0) ); |
michael@0 | 108 | |
michael@0 | 109 | /* |
michael@0 | 110 | Arctan (x) ~ PI/2 - 1/x for large x. For x = 1.6x10^16, 1/x is about the last binary digit of double precision PI/2. |
michael@0 | 111 | That is to say, perturbing PI/2 by this much is about the smallest rounding error possible. |
michael@0 | 112 | |
michael@0 | 113 | This suggests that the answer Christine is getting and a real Infinity are "adjacent" results from the tangent function. I |
michael@0 | 114 | suspect that tan (PI/2 + one ulp) is a negative result about the same size as tan (PI/2) and that this pair are the closest |
michael@0 | 115 | results to infinity that the algorithm can deliver. |
michael@0 | 116 | |
michael@0 | 117 | In any case, my call is that the answer we're seeing is "right". I suggest the test pass on any result this size or larger. |
michael@0 | 118 | = C = |
michael@0 | 119 | */ |
michael@0 | 120 | |
michael@0 | 121 | new TestCase( SECTION, |
michael@0 | 122 | "Math.tan(3*Math.PI/2) >= 5443000000000000", |
michael@0 | 123 | true, |
michael@0 | 124 | Math.tan(3*Math.PI/2) >= 5443000000000000 ); |
michael@0 | 125 | |
michael@0 | 126 | new TestCase( SECTION, |
michael@0 | 127 | "Math.tan(Math.PI/2) >= 5443000000000000", |
michael@0 | 128 | true, |
michael@0 | 129 | Math.tan(Math.PI/2) >= 5443000000000000 ); |
michael@0 | 130 | |
michael@0 | 131 | test(); |