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1 /* -*- Mode: C++; tab-width: 2; indent-tabs-mode: nil; c-basic-offset: 2 -*- */ |
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2 /* This Source Code Form is subject to the terms of the Mozilla Public |
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3 * License, v. 2.0. If a copy of the MPL was not distributed with this |
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4 * file, You can obtain one at http://mozilla.org/MPL/2.0/. */ |
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5 |
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6 /* |
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7 * |
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8 * Date: 31 July 2002 |
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9 * SUMMARY: Testing regexps containing octal escape sequences |
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10 * This is an elaboration of mozilla/js/tests/ecma_2/RegExp/octal-003.js |
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11 * |
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12 * See http://bugzilla.mozilla.org/show_bug.cgi?id=141078 |
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13 * for a reference on octal escape sequences in regexps. |
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14 * |
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15 * NOTE: |
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16 * We will use the identities '\011' === '\u0009' === '\x09' === '\t' |
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17 * |
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18 * The first is an octal escape sequence (\(0-3)OO; O an octal digit). |
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19 * See ECMA-262 Edition 2, Section 7.7.4 "String Literals". These were |
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20 * dropped in Edition 3 but we support them for backward compatibility. |
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21 * |
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22 * The second is a Unicode escape sequence (\uHHHH; H a hex digit). |
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23 * Since octal 11 = hex 9, the two escapes define the same character. |
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24 * |
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25 * The third is a hex escape sequence (\xHH; H a hex digit). |
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26 * Since hex 09 = hex 0009, this defines the same character. |
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27 * |
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28 * The fourth is the familiar escape sequence for a horizontal tab, |
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29 * defined in the ECMA spec as having Unicode value \u0009. |
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30 */ |
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31 //----------------------------------------------------------------------------- |
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32 var i = 0; |
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33 var BUGNUMBER = 141078; |
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34 var summary = 'Testing regexps containing octal escape sequences'; |
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35 var status = ''; |
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36 var statusmessages = new Array(); |
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37 var pattern = ''; |
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38 var patterns = new Array(); |
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39 var string = ''; |
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40 var strings = new Array(); |
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41 var actualmatch = ''; |
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42 var actualmatches = new Array(); |
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43 var expectedmatch = ''; |
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44 var expectedmatches = new Array(); |
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45 |
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46 |
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47 /* |
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48 * Test a string containing the null character '\0' followed by the string '11' |
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49 * |
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50 * 'a' + String.fromCharCode(0) + '11'; |
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51 * |
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52 * Note we can't simply write 'a\011', because '\011' would be interpreted |
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53 * as the octal escape sequence for the tab character (see above). |
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54 * |
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55 * We should get no match from the regexp /.\011/, because it should be |
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56 * looking for the octal escape sequence \011, i.e. the tab character - |
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57 * |
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58 */ |
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59 status = inSection(1); |
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60 pattern = /.\011/; |
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61 string = 'a' + String.fromCharCode(0) + '11'; |
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62 actualmatch = string.match(pattern); |
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63 expectedmatch = null; |
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64 addThis(); |
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65 |
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66 |
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67 /* |
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68 * Try same thing with 'xx' in place of '11'. |
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69 * |
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70 * Should get a match now, because the octal escape sequence in the regexp |
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71 * has been reduced from \011 to \0, and '\0' is present in the string - |
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72 */ |
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73 status = inSection(2); |
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74 pattern = /.\0xx/; |
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75 string = 'a' + String.fromCharCode(0) + 'xx'; |
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76 actualmatch = string.match(pattern); |
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77 expectedmatch = Array(string); |
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78 addThis(); |
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79 |
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80 |
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81 /* |
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82 * Same thing; don't use |String.fromCharCode(0)| this time. |
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83 * There is no ambiguity in '\0xx': it is the null character |
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84 * followed by two x's, no other interpretation is possible. |
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85 */ |
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86 status = inSection(3); |
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87 pattern = /.\0xx/; |
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88 string = 'a\0xx'; |
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89 actualmatch = string.match(pattern); |
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90 expectedmatch = Array(string); |
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91 addThis(); |
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92 |
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93 |
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94 /* |
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95 * This one should produce a match. The two-character string |
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96 * 'a' + '\011' is duplicated in the pattern and test string: |
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97 */ |
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98 status = inSection(4); |
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99 pattern = /.\011/; |
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100 string = 'a\011'; |
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101 actualmatch = string.match(pattern); |
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102 expectedmatch = Array(string); |
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103 addThis(); |
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104 |
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105 |
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106 /* |
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107 * Same as above, only now, for the second character of the string, |
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108 * use the Unicode escape '\u0009' instead of the octal escape '\011' |
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109 */ |
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110 status = inSection(5); |
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111 pattern = /.\011/; |
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112 string = 'a\u0009'; |
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113 actualmatch = string.match(pattern); |
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114 expectedmatch = Array(string); |
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115 addThis(); |
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116 |
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117 |
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118 /* |
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119 * Same as above, only now for the second character of the string, |
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120 * use the hex escape '\x09' instead of the octal escape '\011' |
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121 */ |
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122 status = inSection(6); |
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123 pattern = /.\011/; |
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124 string = 'a\x09'; |
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125 actualmatch = string.match(pattern); |
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126 expectedmatch = Array(string); |
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127 addThis(); |
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128 |
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129 |
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130 /* |
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131 * Same as above, only now for the second character of the string, |
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132 * use the escape '\t' instead of the octal escape '\011' |
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133 */ |
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134 status = inSection(7); |
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135 pattern = /.\011/; |
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136 string = 'a\t'; |
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137 actualmatch = string.match(pattern); |
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138 expectedmatch = Array(string); |
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139 addThis(); |
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140 |
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141 |
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142 /* |
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143 * Return to the string from Section 1. |
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144 * |
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145 * Unlike Section 1, use the RegExp() function to create the |
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146 * regexp pattern: null character followed by the string '11'. |
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147 * |
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148 * Since this is exactly what the string is, we should get a match - |
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149 */ |
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150 status = inSection(8); |
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151 string = 'a' + String.fromCharCode(0) + '11'; |
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152 pattern = RegExp(string); |
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153 actualmatch = string.match(pattern); |
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154 expectedmatch = Array(string); |
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155 addThis(); |
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156 |
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157 |
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158 |
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159 |
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160 //------------------------------------------------------------------------------------------------- |
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161 test(); |
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162 //------------------------------------------------------------------------------------------------- |
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163 |
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164 |
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165 |
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166 function addThis() |
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167 { |
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168 statusmessages[i] = status; |
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169 patterns[i] = pattern; |
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170 strings[i] = string; |
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171 actualmatches[i] = actualmatch; |
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172 expectedmatches[i] = expectedmatch; |
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173 i++; |
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174 } |
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175 |
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176 |
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177 function test() |
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178 { |
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179 enterFunc ('test'); |
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180 printBugNumber(BUGNUMBER); |
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181 printStatus (summary); |
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182 testRegExp(statusmessages, patterns, strings, actualmatches, expectedmatches); |
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183 exitFunc ('test'); |
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184 } |