services/crypto/tests/unit/test_utils_pbkdf2.js

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TOR_BUG_9701
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1 /* Any copyright is dedicated to the Public Domain.
2 * http://creativecommons.org/publicdomain/zero/1.0/ */
3
4 // XXX until bug 937114 is fixed
5 Cu.importGlobalProperties(['btoa']);
6 Cu.import("resource://services-crypto/utils.js");
7 Cu.import("resource://services-common/utils.js");
8
9 let {bytesAsHex: b2h} = CommonUtils;
10
11 function run_test() {
12 run_next_test();
13 }
14
15 add_task(function test_pbkdf2() {
16 let symmKey16 = CryptoUtils.pbkdf2Generate("secret phrase", "DNXPzPpiwn", 4096, 16);
17 do_check_eq(symmKey16.length, 16);
18 do_check_eq(btoa(symmKey16), "d2zG0d2cBfXnRwMUGyMwyg==");
19 do_check_eq(CommonUtils.encodeBase32(symmKey16), "O5WMNUO5TQC7LZ2HAMKBWIZQZI======");
20 let symmKey32 = CryptoUtils.pbkdf2Generate("passphrase", "salt", 4096, 32);
21 do_check_eq(symmKey32.length, 32);
22 });
23
24 // http://tools.ietf.org/html/rfc6070
25 // PBKDF2 HMAC-SHA1 Test Vectors
26 add_task(function test_pbkdf2_hmac_sha1() {
27 let pbkdf2 = CryptoUtils.pbkdf2Generate;
28 let vectors = [
29 {P: "password", // (8 octets)
30 S: "salt", // (4 octets)
31 c: 1,
32 dkLen: 20,
33 DK: h("0c 60 c8 0f 96 1f 0e 71"+
34 "f3 a9 b5 24 af 60 12 06"+
35 "2f e0 37 a6"), // (20 octets)
36 },
37
38 {P: "password", // (8 octets)
39 S: "salt", // (4 octets)
40 c: 2,
41 dkLen: 20,
42 DK: h("ea 6c 01 4d c7 2d 6f 8c"+
43 "cd 1e d9 2a ce 1d 41 f0"+
44 "d8 de 89 57"), // (20 octets)
45 },
46
47 {P: "password", // (8 octets)
48 S: "salt", // (4 octets)
49 c: 4096,
50 dkLen: 20,
51 DK: h("4b 00 79 01 b7 65 48 9a"+
52 "be ad 49 d9 26 f7 21 d0"+
53 "65 a4 29 c1"), // (20 octets)
54 },
55
56 // XXX Uncomment the following test after Bug 968567 lands
57 //
58 // XXX As it stands, I estimate that the CryptoUtils implementation will
59 // take approximately 16 hours in my 2.3GHz MacBook to perform this many
60 // rounds.
61 //
62 // {P: "password", // (8 octets)
63 // S: "salt" // (4 octets)
64 // c: 16777216,
65 // dkLen = 20,
66 // DK: h("ee fe 3d 61 cd 4d a4 e4"+
67 // "e9 94 5b 3d 6b a2 15 8c"+
68 // "26 34 e9 84"), // (20 octets)
69 // },
70
71 {P: "passwordPASSWORDpassword", // (24 octets)
72 S: "saltSALTsaltSALTsaltSALTsaltSALTsalt", // (36 octets)
73 c: 4096,
74 dkLen: 25,
75 DK: h("3d 2e ec 4f e4 1c 84 9b"+
76 "80 c8 d8 36 62 c0 e4 4a"+
77 "8b 29 1a 96 4c f2 f0 70"+
78 "38"), // (25 octets)
79
80 },
81
82 {P: "pass\0word", // (9 octets)
83 S: "sa\0lt", // (5 octets)
84 c: 4096,
85 dkLen: 16,
86 DK: h("56 fa 6a a7 55 48 09 9d"+
87 "cc 37 d7 f0 34 25 e0 c3"), // (16 octets)
88 },
89 ];
90
91 for (let v of vectors) {
92 do_check_eq(v.DK, b2h(pbkdf2(v.P, v.S, v.c, v.dkLen)));
93 }
94 });
95
96 // I can't find any normative ietf test vectors for pbkdf2 hmac-sha256.
97 // The following vectors are derived with the same inputs as above (the sha1
98 // test). Results verified by users here:
99 // https://stackoverflow.com/questions/5130513/pbkdf2-hmac-sha2-test-vectors
100 add_task(function test_pbkdf2_hmac_sha256() {
101 let pbkdf2 = CryptoUtils.pbkdf2Generate;
102 let vectors = [
103 {P: "password", // (8 octets)
104 S: "salt", // (4 octets)
105 c: 1,
106 dkLen: 32,
107 DK: h("12 0f b6 cf fc f8 b3 2c"+
108 "43 e7 22 52 56 c4 f8 37"+
109 "a8 65 48 c9 2c cc 35 48"+
110 "08 05 98 7c b7 0b e1 7b"), // (32 octets)
111 },
112
113 {P: "password", // (8 octets)
114 S: "salt", // (4 octets)
115 c: 2,
116 dkLen: 32,
117 DK: h("ae 4d 0c 95 af 6b 46 d3"+
118 "2d 0a df f9 28 f0 6d d0"+
119 "2a 30 3f 8e f3 c2 51 df"+
120 "d6 e2 d8 5a 95 47 4c 43"), // (32 octets)
121 },
122
123 {P: "password", // (8 octets)
124 S: "salt", // (4 octets)
125 c: 4096,
126 dkLen: 32,
127 DK: h("c5 e4 78 d5 92 88 c8 41"+
128 "aa 53 0d b6 84 5c 4c 8d"+
129 "96 28 93 a0 01 ce 4e 11"+
130 "a4 96 38 73 aa 98 13 4a"), // (32 octets)
131 },
132
133 {P: "passwordPASSWORDpassword", // (24 octets)
134 S: "saltSALTsaltSALTsaltSALTsaltSALTsalt", // (36 octets)
135 c: 4096,
136 dkLen: 40,
137 DK: h("34 8c 89 db cb d3 2b 2f"+
138 "32 d8 14 b8 11 6e 84 cf"+
139 "2b 17 34 7e bc 18 00 18"+
140 "1c 4e 2a 1f b8 dd 53 e1"+
141 "c6 35 51 8c 7d ac 47 e9"), // (40 octets)
142 },
143
144 {P: "pass\0word", // (9 octets)
145 S: "sa\0lt", // (5 octets)
146 c: 4096,
147 dkLen: 16,
148 DK: h("89 b6 9d 05 16 f8 29 89"+
149 "3c 69 62 26 65 0a 86 87"), // (16 octets)
150 },
151 ];
152
153 for (let v of vectors) {
154 do_check_eq(v.DK,
155 b2h(pbkdf2(v.P, v.S, v.c, v.dkLen, Ci.nsICryptoHMAC.SHA256, 32)));
156 }
157 });
158
159 // turn formatted test vectors into normal hex strings
160 function h(hexStr) {
161 return hexStr.replace(/\s+/g, "");
162 }

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