1.1 --- /dev/null Thu Jan 01 00:00:00 1970 +0000
1.2 +++ b/js/src/tests/ecma/GlobalObject/15.1.2.5-2.js Wed Dec 31 06:09:35 2014 +0100
1.3 @@ -0,0 +1,149 @@
1.4 +/* -*- Mode: C++; tab-width: 2; indent-tabs-mode: nil; c-basic-offset: 2 -*- */
1.5 +/* This Source Code Form is subject to the terms of the Mozilla Public
1.6 + * License, v. 2.0. If a copy of the MPL was not distributed with this
1.7 + * file, You can obtain one at http://mozilla.org/MPL/2.0/. */
1.8 +
1.9 +
1.10 +/**
1.11 + File Name: 15.1.2.5-2.js
1.12 + ECMA Section: 15.1.2.5 Function properties of the global object
1.13 + unescape( string )
1.14 + Description:
1.15 +
1.16 + This tests the cases where there are fewer than 4 characters following "%u",
1.17 + or fewer than 2 characters following "%" or "%u".
1.18 +
1.19 + The unescape function computes a new version of a string value in which
1.20 + each escape sequences of the sort that might be introduced by the escape
1.21 + function is replaced with the character that it represents.
1.22 +
1.23 + When the unescape function is called with one argument string, the
1.24 + following steps are taken:
1.25 +
1.26 + 1. Call ToString(string).
1.27 + 2. Compute the number of characters in Result(1).
1.28 + 3. Let R be the empty string.
1.29 + 4. Let k be 0.
1.30 + 5. If k equals Result(2), return R.
1.31 + 6. Let c be the character at position k within Result(1).
1.32 + 7. If c is not %, go to step 18.
1.33 + 8. If k is greater than Result(2)-6, go to step 14.
1.34 + 9. If the character at position k+1 within result(1) is not u, go to step
1.35 + 14.
1.36 + 10. If the four characters at positions k+2, k+3, k+4, and k+5 within
1.37 + Result(1) are not all hexadecimal digits, go to step 14.
1.38 + 11. Let c be the character whose Unicode encoding is the integer represented
1.39 + by the four hexadecimal digits at positions k+2, k+3, k+4, and k+5
1.40 + within Result(1).
1.41 + 12. Increase k by 5.
1.42 + 13. Go to step 18.
1.43 + 14. If k is greater than Result(2)-3, go to step 18.
1.44 + 15. If the two characters at positions k+1 and k+2 within Result(1) are not
1.45 + both hexadecimal digits, go to step 18.
1.46 + 16. Let c be the character whose Unicode encoding is the integer represented
1.47 + by two zeroes plus the two hexadecimal digits at positions k+1 and k+2
1.48 + within Result(1).
1.49 + 17. Increase k by 2.
1.50 + 18. Let R be a new string value computed by concatenating the previous value
1.51 + of R and c.
1.52 + 19. Increase k by 1.
1.53 + 20. Go to step 5.
1.54 + Author: christine@netscape.com
1.55 + Date: 28 october 1997
1.56 +*/
1.57 +
1.58 +var SECTION = "15.1.2.5-2";
1.59 +var VERSION = "ECMA_1";
1.60 +startTest();
1.61 +var TITLE = "unescape(string)";
1.62 +
1.63 +writeHeaderToLog( SECTION + " "+ TITLE);
1.64 +
1.65 +// since there is only one character following "%", no conversion should occur.
1.66 +
1.67 +for ( var CHARCODE = 0; CHARCODE < 256; CHARCODE += 16 ) {
1.68 + new TestCase( SECTION,
1.69 + "unescape( %"+ (ToHexString(CHARCODE)).substring(0,1) +" )",
1.70 + "%"+(ToHexString(CHARCODE)).substring(0,1),
1.71 + unescape( "%" + (ToHexString(CHARCODE)).substring(0,1) ) );
1.72 +}
1.73 +
1.74 +// since there is only one character following "%u", no conversion should occur.
1.75 +
1.76 +for ( var CHARCODE = 0; CHARCODE < 256; CHARCODE +=16 ) {
1.77 + new TestCase( SECTION,
1.78 + "unescape( %u"+ (ToHexString(CHARCODE)).substring(0,1) +" )",
1.79 + "%u"+(ToHexString(CHARCODE)).substring(0,1),
1.80 + unescape( "%u" + (ToHexString(CHARCODE)).substring(0,1) ) );
1.81 +}
1.82 +
1.83 +
1.84 +// three char unicode string. no conversion should occur
1.85 +
1.86 +for ( var CHARCODE = 1024; CHARCODE < 65536; CHARCODE+= 1234 ) {
1.87 + new TestCase
1.88 + ( SECTION,
1.89 + "unescape( %u"+ (ToUnicodeString(CHARCODE)).substring(0,3)+ " )",
1.90 +
1.91 + "%u"+(ToUnicodeString(CHARCODE)).substring(0,3),
1.92 + unescape( "%u"+(ToUnicodeString(CHARCODE)).substring(0,3) )
1.93 + );
1.94 +}
1.95 +
1.96 +test();
1.97 +
1.98 +function ToUnicodeString( n ) {
1.99 + var string = ToHexString(n);
1.100 +
1.101 + for ( var PAD = (4 - string.length ); PAD > 0; PAD-- ) {
1.102 + string = "0" + string;
1.103 + }
1.104 +
1.105 + return string;
1.106 +}
1.107 +function ToHexString( n ) {
1.108 + var hex = new Array();
1.109 +
1.110 + for ( var mag = 1; Math.pow(16,mag) <= n ; mag++ ) {
1.111 + ;
1.112 + }
1.113 +
1.114 + for ( index = 0, mag -= 1; mag > 0; index++, mag-- ) {
1.115 + hex[index] = Math.floor( n / Math.pow(16,mag) );
1.116 + n -= Math.pow(16,mag) * Math.floor( n/Math.pow(16,mag) );
1.117 + }
1.118 +
1.119 + hex[hex.length] = n % 16;
1.120 +
1.121 + var string ="";
1.122 +
1.123 + for ( var index = 0 ; index < hex.length ; index++ ) {
1.124 + switch ( hex[index] ) {
1.125 + case 10:
1.126 + string += "A";
1.127 + break;
1.128 + case 11:
1.129 + string += "B";
1.130 + break;
1.131 + case 12:
1.132 + string += "C";
1.133 + break;
1.134 + case 13:
1.135 + string += "D";
1.136 + break;
1.137 + case 14:
1.138 + string += "E";
1.139 + break;
1.140 + case 15:
1.141 + string += "F";
1.142 + break;
1.143 + default:
1.144 + string += hex[index];
1.145 + }
1.146 + }
1.147 +
1.148 + if ( string.length == 1 ) {
1.149 + string = "0" + string;
1.150 + }
1.151 + return string;
1.152 +}
