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 /* Any copyright is dedicated to the Public Domain.

  * http://creativecommons.org/publicdomain/zero/1.0/ */

 // XXX until bug 937114 is fixed

 Cu.importGlobalProperties(['btoa']);

 Cu.import("resource://services-crypto/utils.js");

 Cu.import("resource://services-common/utils.js");

 let {bytesAsHex: b2h} = CommonUtils;

 function run_test() {

   run_next_test();

 }

 add_task(function test_pbkdf2() {

   let symmKey16 = CryptoUtils.pbkdf2Generate("secret phrase", "DNXPzPpiwn", 4096, 16);

   do_check_eq(symmKey16.length, 16);

   do_check_eq(btoa(symmKey16), "d2zG0d2cBfXnRwMUGyMwyg==");

   do_check_eq(CommonUtils.encodeBase32(symmKey16), "O5WMNUO5TQC7LZ2HAMKBWIZQZI======");

   let symmKey32 = CryptoUtils.pbkdf2Generate("passphrase", "salt", 4096, 32);

   do_check_eq(symmKey32.length, 32);

 });

 // http://tools.ietf.org/html/rfc6070

 // PBKDF2 HMAC-SHA1 Test Vectors

 add_task(function test_pbkdf2_hmac_sha1() {

   let pbkdf2 = CryptoUtils.pbkdf2Generate;

   let vectors = [

     {P: "password",                    // (8 octets)

      S: "salt",                        // (4 octets)

      c: 1,

      dkLen: 20,

      DK: h("0c 60 c8 0f 96 1f 0e 71"+

            "f3 a9 b5 24 af 60 12 06"+

            "2f e0 37 a6"),             // (20 octets)

     },

     {P: "password",                    // (8 octets)

      S: "salt",                        // (4 octets)

      c: 2,

      dkLen: 20,

      DK: h("ea 6c 01 4d c7 2d 6f 8c"+

            "cd 1e d9 2a ce 1d 41 f0"+

            "d8 de 89 57"),             // (20 octets)

     },

     {P: "password",                    // (8 octets)

      S: "salt",                        // (4 octets)

      c: 4096,

      dkLen: 20,

      DK: h("4b 00 79 01 b7 65 48 9a"+

            "be ad 49 d9 26 f7 21 d0"+

            "65 a4 29 c1"),             // (20 octets)

     },

     // XXX Uncomment the following test after Bug 968567 lands

     //

     // XXX As it stands, I estimate that the CryptoUtils implementation will

     // take approximately 16 hours in my 2.3GHz MacBook to perform this many

     // rounds.

     //

     // {P: "password",                     // (8 octets)

     //  S: "salt"                          // (4 octets)

     //  c: 16777216,

     //  dkLen = 20,

     //  DK: h("ee fe 3d 61 cd 4d a4 e4"+

     //        "e9 94 5b 3d 6b a2 15 8c"+

     //        "26 34 e9 84"),             // (20 octets)

     // },

     {P: "passwordPASSWORDpassword",    // (24 octets)

      S: "saltSALTsaltSALTsaltSALTsaltSALTsalt", // (36 octets)

      c: 4096,

      dkLen: 25,

      DK: h("3d 2e ec 4f e4 1c 84 9b"+

            "80 c8 d8 36 62 c0 e4 4a"+

            "8b 29 1a 96 4c f2 f0 70"+

            "38"),                      // (25 octets)

     },

     {P: "pass\0word",                  // (9 octets)

      S: "sa\0lt",                      // (5 octets)

      c: 4096,

      dkLen: 16,

      DK: h("56 fa 6a a7 55 48 09 9d"+

            "cc 37 d7 f0 34 25 e0 c3"), // (16 octets)

     },

   ];

   for (let v of vectors) {

     do_check_eq(v.DK, b2h(pbkdf2(v.P, v.S, v.c, v.dkLen)));

   }

 });

 // I can't find any normative ietf test vectors for pbkdf2 hmac-sha256.

 // The following vectors are derived with the same inputs as above (the sha1

 // test).  Results verified by users here:

 // https://stackoverflow.com/questions/5130513/pbkdf2-hmac-sha2-test-vectors

 add_task(function test_pbkdf2_hmac_sha256() {

   let pbkdf2 = CryptoUtils.pbkdf2Generate;

   let vectors = [

     {P: "password",                    // (8 octets)

      S: "salt",                        // (4 octets)

      c: 1,

      dkLen: 32,

      DK: h("12 0f b6 cf fc f8 b3 2c"+

            "43 e7 22 52 56 c4 f8 37"+

            "a8 65 48 c9 2c cc 35 48"+

            "08 05 98 7c b7 0b e1 7b"), // (32 octets)

     },

     {P: "password",                    // (8 octets)

      S: "salt",                        // (4 octets)

      c: 2,

      dkLen: 32,

      DK: h("ae 4d 0c 95 af 6b 46 d3"+

            "2d 0a df f9 28 f0 6d d0"+

            "2a 30 3f 8e f3 c2 51 df"+

            "d6 e2 d8 5a 95 47 4c 43"), // (32 octets)

     },

     {P: "password",                    // (8 octets)

      S: "salt",                        // (4 octets)

      c: 4096,

      dkLen: 32,

      DK: h("c5 e4 78 d5 92 88 c8 41"+

            "aa 53 0d b6 84 5c 4c 8d"+

            "96 28 93 a0 01 ce 4e 11"+

            "a4 96 38 73 aa 98 13 4a"), // (32 octets)

     },

     {P: "passwordPASSWORDpassword",    // (24 octets)

      S: "saltSALTsaltSALTsaltSALTsaltSALTsalt", // (36 octets)

      c: 4096,

      dkLen: 40,

      DK: h("34 8c 89 db cb d3 2b 2f"+

            "32 d8 14 b8 11 6e 84 cf"+

            "2b 17 34 7e bc 18 00 18"+

            "1c 4e 2a 1f b8 dd 53 e1"+

            "c6 35 51 8c 7d ac 47 e9"), // (40 octets)

     },

     {P: "pass\0word",                  // (9 octets)

      S: "sa\0lt",                      // (5 octets)

      c: 4096,

      dkLen: 16,

      DK: h("89 b6 9d 05 16 f8 29 89"+

            "3c 69 62 26 65 0a 86 87"), // (16 octets)

     },

   ];

   for (let v of vectors) {

     do_check_eq(v.DK,

         b2h(pbkdf2(v.P, v.S, v.c, v.dkLen, Ci.nsICryptoHMAC.SHA256, 32)));

   }

 });

 // turn formatted test vectors into normal hex strings

 function h(hexStr) {

   return hexStr.replace(/\s+/g, "");

 }