The Tor Browser: gfx/skia/trunk/src/pathops/SkPathOpsQuad.cpp@6474c204b198 (annotated)

gfx/skia/trunk/src/pathops/SkPathOpsQuad.cpp@6474c204b198 (annotated)

gfx/skia/trunk/src/pathops/SkPathOpsQuad.cpp

Wed, 31 Dec 2014 06:09:35 +0100

author: Michael Schloh von Bennewitz <michael@schloh.com>
date: Wed, 31 Dec 2014 06:09:35 +0100
changeset 0: 6474c204b198
permissions: -rw-r--r--

Cloned upstream origin tor-browser at tor-browser-31.3.0esr-4.5-1-build1
revision ID fc1c9ff7c1b2defdbc039f12214767608f46423f for hacking purpose.

 /*
  * Copyright 2012 Google Inc.
  *
  * Use of this source code is governed by a BSD-style license that can be
  * found in the LICENSE file.
  */
 #include "SkIntersections.h"
 #include "SkLineParameters.h"
 #include "SkPathOpsCubic.h"
 #include "SkPathOpsQuad.h"
 #include "SkPathOpsTriangle.h"
 // from http://blog.gludion.com/2009/08/distance-to-quadratic-bezier-curve.html
 // (currently only used by testing)
 double SkDQuad::nearestT(const SkDPoint& pt) const {
     SkDVector pos = fPts[0] - pt;
     // search points P of bezier curve with PM.(dP / dt) = 0
     // a calculus leads to a 3d degree equation :
     SkDVector A = fPts[1] - fPts[0];
     SkDVector B = fPts[2] - fPts[1];
     B -= A;
     double a = B.dot(B);
     double b = 3 * A.dot(B);
     double c = 2 * A.dot(A) + pos.dot(B);
     double d = pos.dot(A);
     double ts[3];
     int roots = SkDCubic::RootsValidT(a, b, c, d, ts);
     double d0 = pt.distanceSquared(fPts[0]);
     double d2 = pt.distanceSquared(fPts[2]);
     double distMin = SkTMin(d0, d2);
     int bestIndex = -1;
     for (int index = 0; index < roots; ++index) {
         SkDPoint onQuad = ptAtT(ts[index]);
         double dist = pt.distanceSquared(onQuad);
         if (distMin > dist) {
             distMin = dist;
             bestIndex = index;
         }
     }
     if (bestIndex >= 0) {
         return ts[bestIndex];
     }
     return d0 < d2 ? 0 : 1;
 }
 bool SkDQuad::pointInHull(const SkDPoint& pt) const {
     return ((const SkDTriangle&) fPts).contains(pt);
 }
 SkDPoint SkDQuad::top(double startT, double endT) const {
     SkDQuad sub = subDivide(startT, endT);
     SkDPoint topPt = sub[0];
     if (topPt.fY > sub[2].fY || (topPt.fY == sub[2].fY && topPt.fX > sub[2].fX)) {
         topPt = sub[2];
     }
     if (!between(sub[0].fY, sub[1].fY, sub[2].fY)) {
         double extremeT;
         if (FindExtrema(sub[0].fY, sub[1].fY, sub[2].fY, &extremeT)) {
             extremeT = startT + (endT - startT) * extremeT;
             SkDPoint test = ptAtT(extremeT);
             if (topPt.fY > test.fY || (topPt.fY == test.fY && topPt.fX > test.fX)) {
                 topPt = test;
             }
         }
     }
     return topPt;
 }
 int SkDQuad::AddValidTs(double s[], int realRoots, double* t) {
     int foundRoots = 0;
     for (int index = 0; index < realRoots; ++index) {
         double tValue = s[index];
         if (approximately_zero_or_more(tValue) && approximately_one_or_less(tValue)) {
             if (approximately_less_than_zero(tValue)) {
                 tValue = 0;
             } else if (approximately_greater_than_one(tValue)) {
                 tValue = 1;
             }
             for (int idx2 = 0; idx2 < foundRoots; ++idx2) {
                 if (approximately_equal(t[idx2], tValue)) {
                     goto nextRoot;
                 }
             }
             t[foundRoots++] = tValue;
         }
 nextRoot:
         {}
     }
     return foundRoots;
 }
 // note: caller expects multiple results to be sorted smaller first
 // note: http://en.wikipedia.org/wiki/Loss_of_significance has an interesting
 //  analysis of the quadratic equation, suggesting why the following looks at
 //  the sign of B -- and further suggesting that the greatest loss of precision
 //  is in b squared less two a c
 int SkDQuad::RootsValidT(double A, double B, double C, double t[2]) {
     double s[2];
     int realRoots = RootsReal(A, B, C, s);
     int foundRoots = AddValidTs(s, realRoots, t);
     return foundRoots;
 }
 /*
 Numeric Solutions (5.6) suggests to solve the quadratic by computing
        Q = -1/2(B + sgn(B)Sqrt(B^2 - 4 A C))
 and using the roots
       t1 = Q / A
       t2 = C / Q
 */
 // this does not discard real roots <= 0 or >= 1
 int SkDQuad::RootsReal(const double A, const double B, const double C, double s[2]) {
     const double p = B / (2 * A);
     const double q = C / A;
     if (approximately_zero(A) && (approximately_zero_inverse(p) || approximately_zero_inverse(q))) {
         if (approximately_zero(B)) {
             s[0] = 0;
             return C == 0;
         }
         s[0] = -C / B;
         return 1;
     }
     /* normal form: x^2 + px + q = 0 */
     const double p2 = p * p;
     if (!AlmostDequalUlps(p2, q) && p2 < q) {
         return 0;
     }
     double sqrt_D = 0;
     if (p2 > q) {
         sqrt_D = sqrt(p2 - q);
     }
     s[0] = sqrt_D - p;
     s[1] = -sqrt_D - p;
     return 1 + !AlmostDequalUlps(s[0], s[1]);
 }
 bool SkDQuad::isLinear(int startIndex, int endIndex) const {
     SkLineParameters lineParameters;
     lineParameters.quadEndPoints(*this, startIndex, endIndex);
     // FIXME: maybe it's possible to avoid this and compare non-normalized
     lineParameters.normalize();
     double distance = lineParameters.controlPtDistance(*this);
     return approximately_zero(distance);
 }
 SkDCubic SkDQuad::toCubic() const {
     SkDCubic cubic;
     cubic[0] = fPts[0];
     cubic[2] = fPts[1];
     cubic[3] = fPts[2];
     cubic[1].fX = (cubic[0].fX + cubic[2].fX * 2) / 3;
     cubic[1].fY = (cubic[0].fY + cubic[2].fY * 2) / 3;
     cubic[2].fX = (cubic[3].fX + cubic[2].fX * 2) / 3;
     cubic[2].fY = (cubic[3].fY + cubic[2].fY * 2) / 3;
     return cubic;
 }
 SkDVector SkDQuad::dxdyAtT(double t) const {
     double a = t - 1;
     double b = 1 - 2 * t;
     double c = t;
     SkDVector result = { a * fPts[0].fX + b * fPts[1].fX + c * fPts[2].fX,
             a * fPts[0].fY + b * fPts[1].fY + c * fPts[2].fY };
     return result;
 }
 // OPTIMIZE: assert if caller passes in t == 0 / t == 1 ?
 SkDPoint SkDQuad::ptAtT(double t) const {
     if (0 == t) {
         return fPts[0];
     }
     if (1 == t) {
         return fPts[2];
     }
     double one_t = 1 - t;
     double a = one_t * one_t;
     double b = 2 * one_t * t;
     double c = t * t;
     SkDPoint result = { a * fPts[0].fX + b * fPts[1].fX + c * fPts[2].fX,
             a * fPts[0].fY + b * fPts[1].fY + c * fPts[2].fY };
     return result;
 }
 /*
 Given a quadratic q, t1, and t2, find a small quadratic segment.
 The new quadratic is defined by A, B, and C, where
  A = c[0]*(1 - t1)*(1 - t1) + 2*c[1]*t1*(1 - t1) + c[2]*t1*t1
  C = c[3]*(1 - t1)*(1 - t1) + 2*c[2]*t1*(1 - t1) + c[1]*t1*t1
 To find B, compute the point halfway between t1 and t2:
 q(at (t1 + t2)/2) == D
 Next, compute where D must be if we know the value of B:
 _12 = A/2 + B/2
 _ = B/2 + C/2
 = A/4 + B/2 + C/4
     = D
 Group the known values on one side:
 B   = D*2 - A/2 - C/2
 */
 static double interp_quad_coords(const double* src, double t) {
     double ab = SkDInterp(src[0], src[2], t);
     double bc = SkDInterp(src[2], src[4], t);
     double abc = SkDInterp(ab, bc, t);
     return abc;
 }
 bool SkDQuad::monotonicInY() const {
     return between(fPts[0].fY, fPts[1].fY, fPts[2].fY);
 }
 SkDQuad SkDQuad::subDivide(double t1, double t2) const {
     SkDQuad dst;
     double ax = dst[0].fX = interp_quad_coords(&fPts[0].fX, t1);
     double ay = dst[0].fY = interp_quad_coords(&fPts[0].fY, t1);
     double dx = interp_quad_coords(&fPts[0].fX, (t1 + t2) / 2);
     double dy = interp_quad_coords(&fPts[0].fY, (t1 + t2) / 2);
     double cx = dst[2].fX = interp_quad_coords(&fPts[0].fX, t2);
     double cy = dst[2].fY = interp_quad_coords(&fPts[0].fY, t2);
     /* bx = */ dst[1].fX = 2*dx - (ax + cx)/2;
     /* by = */ dst[1].fY = 2*dy - (ay + cy)/2;
     return dst;
 }
 void SkDQuad::align(int endIndex, SkDPoint* dstPt) const {
     if (fPts[endIndex].fX == fPts[1].fX) {
         dstPt->fX = fPts[endIndex].fX;
     }
     if (fPts[endIndex].fY == fPts[1].fY) {
         dstPt->fY = fPts[endIndex].fY;
     }
 }
 SkDPoint SkDQuad::subDivide(const SkDPoint& a, const SkDPoint& c, double t1, double t2) const {
     SkASSERT(t1 != t2);
     SkDPoint b;
 #if 0
     // this approach assumes that the control point computed directly is accurate enough
     double dx = interp_quad_coords(&fPts[0].fX, (t1 + t2) / 2);
     double dy = interp_quad_coords(&fPts[0].fY, (t1 + t2) / 2);
     b.fX = 2 * dx - (a.fX + c.fX) / 2;
     b.fY = 2 * dy - (a.fY + c.fY) / 2;
 #else
     SkDQuad sub = subDivide(t1, t2);
     SkDLine b0 = {{a, sub[1] + (a - sub[0])}};
     SkDLine b1 = {{c, sub[1] + (c - sub[2])}};
     SkIntersections i;
     i.intersectRay(b0, b1);
     if (i.used() == 1) {
         b = i.pt(0);
     } else {
         SkASSERT(i.used() == 2 || i.used() == 0);
         b = SkDPoint::Mid(b0[1], b1[1]);
     }
 #endif
     if (t1 == 0 || t2 == 0) {
         align(0, &b);
     }
     if (t1 == 1 || t2 == 1) {
         align(2, &b);
     }
     if (precisely_subdivide_equal(b.fX, a.fX)) {
         b.fX = a.fX;
     } else if (precisely_subdivide_equal(b.fX, c.fX)) {
         b.fX = c.fX;
     }
     if (precisely_subdivide_equal(b.fY, a.fY)) {
         b.fY = a.fY;
     } else if (precisely_subdivide_equal(b.fY, c.fY)) {
         b.fY = c.fY;
     }
     return b;
 }
 /* classic one t subdivision */
 static void interp_quad_coords(const double* src, double* dst, double t) {
     double ab = SkDInterp(src[0], src[2], t);
     double bc = SkDInterp(src[2], src[4], t);
     dst[0] = src[0];
     dst[2] = ab;
     dst[4] = SkDInterp(ab, bc, t);
     dst[6] = bc;
     dst[8] = src[4];
 }
 SkDQuadPair SkDQuad::chopAt(double t) const
 {
     SkDQuadPair dst;
     interp_quad_coords(&fPts[0].fX, &dst.pts[0].fX, t);
     interp_quad_coords(&fPts[0].fY, &dst.pts[0].fY, t);
     return dst;
 }
 static int valid_unit_divide(double numer, double denom, double* ratio)
 {
     if (numer < 0) {
         numer = -numer;
         denom = -denom;
     }
     if (denom == 0 || numer == 0 || numer >= denom) {
         return 0;
     }
     double r = numer / denom;
     if (r == 0) {  // catch underflow if numer <<<< denom
         return 0;
     }
     *ratio = r;
     return 1;
 }
 /** Quad'(t) = At + B, where
     A = 2(a - 2b + c)
     B = 2(b - a)
     Solve for t, only if it fits between 0 < t < 1
 */
 int SkDQuad::FindExtrema(double a, double b, double c, double tValue[1]) {
     /*  At + B == 0
         t = -B / A
     */
     return valid_unit_divide(a - b, a - b - b + c, tValue);
 }
 /* Parameterization form, given A*t*t + 2*B*t*(1-t) + C*(1-t)*(1-t)
  *
  * a = A - 2*B +   C
  * b =     2*B - 2*C
  * c =             C
  */
 void SkDQuad::SetABC(const double* quad, double* a, double* b, double* c) {
     *a = quad[0];      // a = A
     *b = 2 * quad[2];  // b =     2*B
     *c = quad[4];      // c =             C
     *b -= *c;          // b =     2*B -   C
     *a -= *b;          // a = A - 2*B +   C
     *b -= *c;          // b =     2*B - 2*C
 }
 #ifdef SK_DEBUG
 void SkDQuad::dump() {
     SkDebugf("{{");
     int index = 0;
     do {
         fPts[index].dump();
         SkDebugf(", ");
     } while (++index < 2);
     fPts[index].dump();
     SkDebugf("}}\n");
 }
 #endif

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gfx/skia/trunk/src/pathops/SkPathOpsQuad.cpp@6474c204b198 (annotated)

gfx/skia/trunk/src/pathops/SkPathOpsQuad.cpp